You have the same answer as me only you solved for x[1] with x[2] and x[1] with x[3] to get your answer, I did it with x[1] and [2] and x[2] = x[3]. By the way, you can still cancel out bcei.I got this:
z=(a²fl-abel-adfi+bdei+abhi-bdei-a²hj+adej)/(abgi-bcei-acfi+bcei+acej-a²gj+a²fk-abek)
Actually, I worked with y first.You have the same answer as me only you solved for x[1] with x[2] and x[1] with x[3] to get your answer, I did it with x[1] and [2] and x[2] = x[3]. By the way, you can still cancel out bcei.I got this:
z=(a²fl-abel-adfi+bdei+abhi-bdei-a²hj+adej)/(abgi-bcei-acfi+bcei+acej-a²gj+a²fk-abek)
You're only 11, it could explainHOW ARE YOU ALL SO GOOD AT MATH THIS IS SO UNFAIR.
Oh~You're only 11, it could explainHOW ARE YOU ALL SO GOOD AT MATH THIS IS SO UNFAIR.
They are at least 15 year old or older.
I'm 13 and a halfYou're only 11, it could explain
They are at least 15 year old or older.
Well, someday you'll learn higher mathematicsOh~You're only 11, it could explainHOW ARE YOU ALL SO GOOD AT MATH THIS IS SO UNFAIR.
They are at least 15 year old or older.
EDIT: Damn, I'll never be able to understand them now.
You sure about that? ._.Well, someday you'll learn higher mathematicsOh~You're only 11, it could explain
They are at least 15 year old or older.
EDIT: Damn, I'll never be able to understand them now.
Well, you'll get it sooner or later. It's just simple substitutionYou sure about that? ._.
I've always sucked at Maths, truth be told... *weakest subject is Maths*
I'm only 11 ._.Well, you'll get it sooner or later. It's just simple substitutionYou sure about that? ._.
I've always sucked at Maths, truth be told... *weakest subject is Maths*
What kind of sorcery is this. I... my.. my brain...why...I don't even..my brain just melted.What I did:
x = (d - by - cz)/a
x = (h - fy - gz)/e
x = (l - kz - jy)/i
(d-by-cz)/a = (h-fy-gz)/e
ah - fay - agz = ed - bey - ecz
bey - fay = ed - ecz - ah + agz
y = (ed - ecz - ah + agz)/(be - fa)
(h - fy - gz)/e = (l - kz - jy)/i -->
y = (el - kez - ih + giz)/(je - fi)
(ed - ecz - ah + agz)/(be - fa) = (el - kez - ih + giz)/(je - fi) -->
z(jce² + gibe + kefa - bke² - jeag - fiec) = jde² - jeah - fied + fiag - ble² + beih + feal - faih
z = (jde² - jeah - fied + fiag - ble² + beih + feal - faih)/(jce² + gibe + kefa - bke² - jeag - fiec)
Though, I have no idea if either one of ours is correct because it's an absolute chaos with all those variables. (Maybe they're the same just written differently)
What kind of sorcery is this. I... my.. my brain...why...I don't even..my brain just melted.
Well, it's to find a formula to solve simultaneous equations with 3 unknowns.Nevermind the answer - what's this used for?