[Insert Eureka]

EUREKA?


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D

Deleted member 4601

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I got this:

z=(a²fl-abel-adfi+bdei+abhi-bdei-a²hj+adej)/(abgi-acfi+acej-a²gj+a²fk-abek)
 
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D

Deleted member 4601

Guest
I got this:

z=(a²fl-abel-adfi+bdei+abhi-bdei-a²hj+adej)/(abgi-bcei-acfi+bcei+acej-a²gj+a²fk-abek)
You have the same answer as me only you solved for x[1] with x[2] and x[1] with x[3] to get your answer, I did it with x[1] and [2] and x[2] = x[3]. By the way, you can still cancel out bcei.
Actually, I worked with y first. :p
 

Faliara

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DaniGrenade

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What I did:

x = (d - by - cz)/a
x = (h - fy - gz)/e
x = (l - kz - jy)/i

(d-by-cz)/a = (h-fy-gz)/e
ah - fay - agz = ed - bey - ecz
bey - fay = ed - ecz - ah + agz
y = (ed - ecz - ah + agz)/(be - fa)

(h - fy - gz)/e = (l - kz - jy)/i -->
y = (el - kez - ih + giz)/(je - fi)

(ed - ecz - ah + agz)/(be - fa) = (el - kez - ih + giz)/(je - fi) -->
z(jce² + gibe + kefa - bke² - jeag - fiec) = jde² - jeah - fied + fiag - ble² + beih + feal - faih
z = (jde² - jeah - fied + fiag - ble² + beih + feal - faih)/(jce² + gibe + kefa - bke² - jeag - fiec)

Though, I have no idea if either one of ours is correct because it's an absolute chaos with all those variables. (Maybe they're the same just written differently)
What kind of sorcery is this. I... my.. my brain...why...I don't even..my brain just melted.